Kay Jewelers: Sterling Silver Necklaces & Rings Only $30 w/ Free 2-Day Shipping (Regularly $99)
Every Kiss 👄 Begins with Kay!
Now through December 25th, Kay Jewelers is offering up an extra 70% off select Sterling Silver Jewelry found HERE with promo code AF08-00000-01010 at checkout! These jewelry items are all priced at $99.99,so only $30 after the code and you’ll score FREE 2-day shipping with ANY purchase!
OR, you can score an additional 60% off the select Jewlery found HERE when you use promo code AF07-00000-01011 at checkout. I spotted various Sterling Silver earrings and necklaces priced at $99.99 so just $40 each shipped after the 60% off code at checkout!
Code doesn’t work on the earrings. 🙁
How odd, I am still finding code AF07-00000-01011 to work on the $99.99 earrings through the link in the post. Are you on a mobile device? If not, be sure to try it in a different browser. Hope this helps!
Hmm it says nothing in cart qualifies for code? I added one of the earrings
Hi Flavia, make sure you are using the correct code with the items in the corresponding link(s). The items in the first paragraph are 70% off and have one promo code and the items at the bottom are 60% off with a different code. Hope that makes sense?
Worked for me!!! 🙂
Glad to hear it! 😉
It doesn’t give me a spot to enter promo code
Be sure to head to your cart to enter the promo code. Hope this helps!
Just bought the ring in the picture. Ruby is my birthstone.
Wow thanks grabbed this for a friend who broke her necklace!!!
So glad you could grab her a replacement! YW!
Ebates 15%!
Thanks for the tip, but I couldn’t get code to work on a few items on the page. Live chatted and horrible customer service. Frustrated and disappointed. May still order a different pair of earrings on the page, but not all items are showing up as qualifying.
Hmm, be sure to use the correct code for the link you click through as listed above. Hope this helps!
Really wanted to get this deal but the website is super slow and the promotion code took a few tries to load.